Kamis, 02 April 2015

Transformation



A point of K has segment of AB. K isn’t has AB. And A  line of g make  g parallel with AB. And distance between K and AB as twice more than distance between k and g. There is a domain T with range from AB and the range of g. and then that if p has AB then T (P) = p’ KP  


a.     What the shape of  set P’ . if  The P’ move on segment of AB ?      
b.     Prove that T is injectif  !
c.      If E and F are two point of AB. Are they distance of E’ F’ if E’ = T (E) and F’ = T(F) ? 
∠ KEF= ∠ KE^' F (alternate angles) ∠KFE= ∠KF^' E (altenate angles) ∠EKF= ∠E^' KF (opposite angles) 
           Look at the triangle
 


EKF and E’K F’



 



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