A point of K has segment of AB. K isn’t has AB. And
A line of g make g parallel with AB. And distance between K and
AB as twice more than distance between k and g. There is a domain T with range
from AB and the range of g. and then that if p has AB then T (P) = p’ KP
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a. What
the shape of set P’ . if The P’ move on segment of AB ?
b. Prove
that T is injectif !

Look at the triangle
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