Number 3

Ascertainable : three point of A, R, S aren’t collinear. They have domain T that definition :

T (A) = A. T (P)= P’ such that P as point center of AP

The Question :

      a.       Draw R’ = T(R)

      b.       Draw Z such that T (Z) = S

      c.        Is T transformation ?

 

The explained of c :

Is that function v to v ?...

Yes, because every element has onto functions.

      Ø  Is that surjektif ? yes, because they have P’ = T (P),  A  = T(A). the definition at question

      Ø  Is that Injektif ? yes, because every domain has different relation.

Those are proved transformation