half of the rotation QQQQQ

3 Given the triangle of ABC  and the parallelogram of WXYZ. There is point of K at the outside of ABC and WXYZ

~ Draw Sk (triangle of ABC)

 

~ Determine a point of J such that Sg (WXYZ) = WXYZ

 

That is proved Sg (WXYZ) = WXYZ

half of the rotation

Number 2

Given the line of g and point A, A isn’t member g.

1 draw the line of g^1 = SA (g) why SA (g) is line ?

So the point to near that get line

2 prove that g’//g^1

Using a gradient that is m1 equals m2 = g1 // g

(-a,d) (c,d)

y-d/d-d = x-a/c-a

0 = 0

Y = mx + c

M=0

M1 = m2

0 = 0

Half of The Rotation

Half of the rotation properties

1.       It has invers

2.       It has direct isometry