If the point of A (1,3) and B (-2,1). Determine
line equation of g such that Mg (A) =
Answer :
Firstly, find out of line gradient from two point
Y2-y1/x2-x1 = -1-3/-2-1 = -4/-3 = 4/3
Because it’s perpendicular, then m1.m2 =
-1
M2 = -3/4
Secondly, find out the center point
(x1 + x2/ 2) , (y2+y1/2)
(-2+1/2), (-1+3/2)
(-1/2, 1)
The last, find out equation of line from
(-1/2, 1)
y-y1 = m ( x-x1)
y-1 = -3/4 (x+1/2)
y-1 = -3/4 x – 3/8
y = -3/4 x + 5/8
8y = -6x + 5
X = 0 then y = 5/8
Y = 0
then x = 5 / 6
The line equation is 6x + 8y – 5 = 0
