half of the rotation QQQQQ 3 Given the triangle of ABC and the parallelogram of WXYZ. There is point of K at the outside of ABC and WXYZ ~ Draw Sk (triangle of ABC) ~ Determine a point of J such that Sg (WXYZ) = WXYZ That is proved Sg (WXYZ) = WXYZ Kirimkan Ini lewat EmailBlogThis!Bagikan ke XBerbagi ke Facebook
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