half of the rotation

Number 2

Given the line of g and point A, A isn’t member g.

1 draw the line of g^1 = SA (g) why SA (g) is line ?

So the point to near that get line

2 prove that g’//g^1

Using a gradient that is m1 equals m2 = g1 // g

(-a,d) (c,d)

y-d/d-d = x-a/c-a

0 = 0

Y = mx + c

M=0

M1 = m2

0 = 0